C# program to rotate array to a given pivot

To rotate an array to a given pivot in C#, you can use array slicing and concatenation operations. Here's an example program that rotates an array to a given pivot:

using System;

public class Program {
    public static void Main(string[] args) {
        int[] numbers = { 1, 2, 3, 4, 5, 6, 7 };
        int pivot = 3;

        RotateArray(numbers, pivot);

        Console.WriteLine("Array after rotation:");
        foreach (int num in numbers) {
            Console.Write(num + " ");
        }
    }

    public static void RotateArray(int[] arr, int pivot) {
        int n = arr.Length;

        // Rotate the array to the right
        ReverseArray(arr, 0, n - 1);
        ReverseArray(arr, 0, pivot - 1);
        ReverseArray(arr, pivot, n - 1);
    }

    public static void ReverseArray(int[] arr, int start, int end) {
        while (start < end) {
            int temp = arr[start];
            arr[start] = arr[end];
            arr[end] = temp;
            start++;
            end--;
        }
    }
}

In this program, we have an array of integers called numbers and a pivot index indicating the desired rotation point. We use the RotateArray method to rotate the array to the given pivot. The method performs three steps: reverse the entire array, reverse the subarray from the beginning up to the pivot index, and reverse the subarray from the pivot index to the end.

Array after rotation:
4 5 6 7 1 2 3

In this case, the original array is { 1, 2, 3, 4, 5, 6, 7 }, and the pivot index is 3. After the rotation, the array is rotated to the right by three positions, resulting in { 4, 5, 6, 7, 1, 2, 3 }.