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Implementation of countDigits(int) Function

To implement a countDigits(int) function in C that counts the number of digits in an integer, you can use a simple iterative approach. Here's an example of how to implement the countDigits() function:

Example:


#include <stdio.h>

// Function to count the number of digits in an integer
int countDigits(int num) {
    int count = 0;

    // Handle the case of 0 separately
    if (num == 0) {
        return 1;
    }

    while (num != 0) {
        // Increment the count for each digit
        count++;
        num /= 10;
    }

    return count;
}

int main() {
    int number = 12345;
    int digitCount = countDigits(number);

    printf("Number of digits in %d: %d\n", number, digitCount);

    return 0;
}

In this example:

  • The countDigits() function takes an integer num as its parameter and initializes a variable count to 0.
  • It handles the case of num being 0 separately because 0 has one digit.
  • Inside the while loop, the function repeatedly divides num by 10 and increments the count variable for each digit until num becomes 0.
  • The function returns the count as the number of digits in the integer.
  • In the main() function, a number (12345 in this case) is passed to the countDigits() function, and the digit count is stored in the digitCount variable.
  • Finally, the program prints the number of digits in the original number.

Output:


Number of digits in 12345: 5

You can use this countDigits() function to count the number of digits in any integer by passing it as an argument to the function.

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